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Find the break even points of the polynomial $4x^2\left(\left(3-x\right)^2+1\right)$ by putting it in the form of an equation and then set it equal to zero
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$4x^2\left(\left(3-x\right)^2+1\right)=0$
Learn how to solve integral calculus problems step by step online. Find the break even points of the expression 4x^2((3-x)^2+1). Find the break even points of the polynomial 4x^2\left(\left(3-x\right)^2+1\right) by putting it in the form of an equation and then set it equal to zero. A binomial squared (difference) is equal to the square of the first term, minus the double product of the first by the second, plus the square of the second term. In other words: (a-b)^2=a^2-2ab+b^2. Add the values 9 and 1. Divide both sides of the equation by 4.