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To find the roots of a polynomial of the form $ax^2+bx+c$ we use the quadratic formula, where in this case $a=3$, $b=-4$ and $c=5$. Then substitute the values of the coefficients of the equation in the quadratic formula: $\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$
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$w=\frac{4\pm \sqrt{{\left(-4\right)}^2-4\cdot 3\cdot 5}}{2\cdot 3}$
Learn how to solve differential calculus problems step by step online. Find the break even points of the expression 3w^2-4w+5=0. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=3, b=-4 and c=5. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Simplifying. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-). Calculate the power \sqrt{-44} using complex numbers.