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Find the break even points of the polynomial $3\left(2y\right)^2+5\cdot 2y-1\cdot {\left(-1\right)}^2$ by putting it in the form of an equation and then set it equal to zero
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$3\left(2y\right)^2+5\cdot 2y-1\cdot {\left(-1\right)}^2=0$
Learn how to solve problems step by step online. Find the break even points of the expression 3(2y)^2+5*2y-(-1)^2. Find the break even points of the polynomial 3\left(2y\right)^2+5\cdot 2y-1\cdot {\left(-1\right)}^2 by putting it in the form of an equation and then set it equal to zero. Multiply 5 times 2. The power of a product is equal to the product of it's factors raised to the same power. The product of powers of the same base is equal to the base raised to the sum of the exponents: a^m\cdot a^n=a^{m+n}.