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Find the break even points of the polynomial $2x-3\left(x-3\right)^2$ by putting it in the form of an equation and then set it equal to zero
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$2x-3\left(x-3\right)^2=0$
Learn how to solve classify algebraic expressions problems step by step online. Find the break even points of the expression 2x-3(x-3)^2. Find the break even points of the polynomial 2x-3\left(x-3\right)^2 by putting it in the form of an equation and then set it equal to zero. A binomial squared (difference) is equal to the square of the first term, minus the double product of the first by the second, plus the square of the second term. In other words: (a-b)^2=a^2-2ab+b^2. Multiply the single term -3 by each term of the polynomial \left(x^2-6x+9\right). Combining like terms 2x and 18x.