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$2x^2+5x-100=0$
Learn how to solve limits by direct substitution problems step by step online. Find the break even points of the expression 2x^2+5x=100. Rewrite the equation. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=2, b=5 and c=-100. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Simplifying. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-).