Final answer to the problem
$2y^2-2\sin\left(2x\right)$
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Step-by-step Solution
Specify the solving method
1
Any expression multiplied by $1$ is equal to itself
$2\left(y^2-\sin\left(2x\right)\right)$
2
Multiply the single term $2$ by each term of the polynomial $\left(y^2-\sin\left(2x\right)\right)$
$2y^2-2\sin\left(2x\right)$
Final answer to the problem
$2y^2-2\sin\left(2x\right)$