$3x+y+2x+2+7y$
$\left(x+y\left(3+x\right)\right)^2$
$a^4\left(a+b\right)$
$x^3-13x-12$
$4\int\sec^3\text{d}\theta$
$\frac{y^4}{4}+\frac{1}{4y^4}+\frac{3}{2}$
$15^{5x-120}=1$
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