Final Answer
$7\sqrt[4]{a^{5}}\sqrt{b}\left(2c^{4}-\sqrt[4]{c}\right)$
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Step-by-step Solution
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The power of a product is equal to the product of it's factors raised to the same power
$14\sqrt[4]{a^{5}}\sqrt{b}c^4-7a\sqrt[4]{c}\sqrt[4]{a}\sqrt[4]{b^2}$
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$14\sqrt[4]{a^{5}}\sqrt{b}c^4-7a\sqrt[4]{c}\sqrt[4]{a}\sqrt[4]{b^2}$
Learn how to solve polynomial factorization problems step by step online. Factor by completing the square 14(a^5b^2)^1/4c^4-7a(cab^2)^1/4. The power of a product is equal to the product of it's factors raised to the same power. The power of a product is equal to the product of it's factors raised to the same power. . Simplify \sqrt[4]{a^5} using the power of a power property: \left(a^m\right)^n=a^{m\cdot n}. In the expression, m equals 5 and n equals \frac{1}{4}.
Final Answer
$7\sqrt[4]{a^{5}}\sqrt{b}\left(2c^{4}-\sqrt[4]{c}\right)$