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$\int\left(\frac{13}{10}b+\frac{39}{5}-\frac{16}{5}b\right)db$
Learn how to solve integral calculus problems step by step online. Find the integral of 13/10b+39/5-16/5b. Find the integral. Simplify the expression inside the integral. The integral \int-\frac{19}{10}bdb results in: -\frac{19}{20}b^2. The integral \int\frac{39}{5}db results in: \frac{39}{5}b.