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Find the roots of $1-3\ln\left(x\right)\sec\left(x\right)^2=1-6\sec\left(x\right)$

Step-by-step Solution

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Final answer to the problem

$x=\mathrm{arcsec}\left(0\right)$
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Step-by-step Solution

How should I solve this problem?

  • Find the roots
  • Solve for x
  • Solve by factoring
  • Solve by completing the square
  • Solve by quadratic formula (general formula)
  • Find break even points
  • Find the discriminant
  • Integrate by partial fractions
  • Product of Binomials with Common Term
  • FOIL Method
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Can't find a method? Tell us so we can add it.
1

Group the terms of the equation by moving the terms that have the variable $x$ to the left side, and those that do not have it to the right side

$-3\ln\left(x\right)\sec\left(x\right)^2+6\sec\left(x\right)=1-1$

Learn how to solve integral calculus problems step by step online.

$-3\ln\left(x\right)\sec\left(x\right)^2+6\sec\left(x\right)=1-1$

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Learn how to solve integral calculus problems step by step online. Find the roots of 1-3ln(x)sec(x)^2=1-6sec(x). Group the terms of the equation by moving the terms that have the variable x to the left side, and those that do not have it to the right side. Subtract the values 1 and -1. Factor the polynomial -3\ln\left(x\right)\sec\left(x\right)^2+6\sec\left(x\right) by it's greatest common factor (GCF): 3\sec\left(x\right). Divide both sides of the equation by 3.

Final answer to the problem

$x=\mathrm{arcsec}\left(0\right)$

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Function Plot

Plotting: $1-3\ln\left(x\right)\sec\left(x\right)^2-1+6\sec\left(x\right)$

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Integral Calculus

Integration assigns numbers to functions in a way that can describe displacement, area, volume, and other concepts that arise by combining infinitesimal data.

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