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Find the break even points of the expression $-\left(\left(2\cdot -1\right)^{25}\right)^2+\left(1\cdot 5\cdot -1\right)^2$

Step-by-step Solution

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Final Answer

$-1\cdot {\left(-2\right)}^{50}+25$
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Step-by-step Solution

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Multiply $2$ times $-1$

$-\left({\left(-2\right)}^{25}\right)^2+\left(1\cdot 5\cdot -1\right)^2$

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$-\left({\left(-2\right)}^{25}\right)^2+\left(1\cdot 5\cdot -1\right)^2$

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Learn how to solve classify algebraic expressions problems step by step online. Find the break even points of the expression -(2*-)^25^2+(1*5*-)^2. Multiply 2 times -1. Multiply 1 times 5. Multiply 5 times -1. Simplify \left({\left(-2\right)}^{25}\right)^2 using the power of a power property: \left(a^m\right)^n=a^{m\cdot n}. In the expression, m equals 25 and n equals 2.

Final Answer

$-1\cdot {\left(-2\right)}^{50}+25$

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Function Plot

Plotting: $-1\cdot {\left(-2\right)}^{50}+25$

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5
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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Classify algebraic expressions

An algebraic expression can be classified as a monomial, binomial, trinomial or polynomial, depending on the number of terms.

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