Final Answer
$-\frac{1}{6}x^2-\frac{1}{2}\ln\left(1+x^2\right)$
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Step-by-step Solution
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1
Take $\frac{-\frac{1}{3}}{2}$ out of the fraction
$-\frac{1}{6}x^2-\frac{1}{2}\ln\left(1+x^2\right)$
Final Answer
$-\frac{1}{6}x^2-\frac{1}{2}\ln\left(1+x^2\right)$