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Solve the equation with radicals $\sqrt{25y-6}=4\sqrt{y+3}$

Step-by-step Solution

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Solution

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Final Answer

$y=6$
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Step-by-step Solution

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Removing the variable's exponent raising both sides of the equation to the power of $2$

$25y-6=\left(4\sqrt{y+3}\right)^{2}$

Learn how to solve integrals involving logarithmic functions problems step by step online.

$25y-6=\left(4\sqrt{y+3}\right)^{2}$

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Learn how to solve integrals involving logarithmic functions problems step by step online. Solve the equation with radicals (25y-6)^1/2=4(y+3)^1/2. Removing the variable's exponent raising both sides of the equation to the power of 2. The power of a product is equal to the product of it's factors raised to the same power. Solve the product 16\left(y+3\right). Group the terms of the equation by moving the terms that have the variable y to the left side, and those that do not have it to the right side.

Final Answer

$y=6$

Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

Solve for yFind the rootsSolve by completing the squareSolve by quadratic formula (general formula)Find break even pointsFind the discriminant

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Function Plot

Plotting: $\sqrt{25y-6}-4\sqrt{y+3}$

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5
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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
◻2
◻◻
√◻
√

◻√◻
◻√
∞
e
π
ln
log
log◻
lim
d/dx
D□x
∫
∫◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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Main Topic: Integrals involving Logarithmic Functions

They are those integrals where the function that we are integrating is composed only of combinations of logarithmic functions.

Used Formulas

2. See formulas

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