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Find the break even points of the expression $\sqrt{\left(3-3\right)^2+\left(6-y\right)^2}=10^2$

Step-by-step Solution

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Final Answer

$y=-94$
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Step-by-step Solution

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Subtract the values $3$ and $-3$

$\sqrt{0^2+\left(6-y\right)^2}=10^2$

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$\sqrt{0^2+\left(6-y\right)^2}=10^2$

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Learn how to solve classify algebraic expressions problems step by step online. Find the break even points of the expression ((3-3)^2+(6-y)^2)^1/2=10^2. Subtract the values 3 and -3. Removing the variable's exponent raising both sides of the equation to the power of 2. Removing the variable's exponent raising both sides of the equation to the power of \frac{1}{2}. We need to isolate the dependent variable , we can do that by simultaneously subtracting 6 from both sides of the equation.

Final Answer

$y=-94$

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Solve for yFind the rootsSolve by factoringSolve by completing the squareSolve by quadratic formula (general formula)Find the discriminant

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Function Plot

Plotting: $\sqrt{\left(3-3\right)^2+\left(6-y\right)^2}-1\cdot 10^2$

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1
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5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Classify algebraic expressions

An algebraic expression can be classified as a monomial, binomial, trinomial or polynomial, depending on the number of terms.

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