$\frac{d}{dx}\left(\sqrt{\left(-2-x\right)^2+\left(3-4\right)^2}-4\right)=\frac{-\left(-2-x\right)}{\sqrt{\left(-2-x\right)^2+1}}$
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Integral
$\int\left(\sqrt{\left(-2-x\right)^2+\left(3-4\right)^2}-4\right)dx=\frac{\left(-2-x\right)\sqrt{\left(-2-x\right)^2+1}}{2}-\frac{1}{2}\ln\left(\sqrt{\left(-2-x\right)^2+1}-2-x\right)+\left(2+x\right)\sqrt{\left(-2-x\right)^2+1}-4x+C_0$
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