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Find the break even points of the polynomial $\sqrt[3]{\left(7x-6\right)\left(x-3\right)\left(8x+9\right)}$ by putting it in the form of an equation and then set it equal to zero
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$\sqrt[3]{\left(7x-6\right)\left(x-3\right)\left(8x+9\right)}=0$
Learn how to solve classify algebraic expressions problems step by step online. Find the break even points of the expression ((7x-6)(x-3)(8x+9))^1/3. Find the break even points of the polynomial \sqrt[3]{\left(7x-6\right)\left(x-3\right)\left(8x+9\right)} by putting it in the form of an equation and then set it equal to zero. Removing the variable's exponent raising both sides of the equation to the power of 3. Divide 1 by \frac{1}{3}. Simplify \left(\sqrt[3]{\left(7x-6\right)\left(x-3\right)\left(8x+9\right)}\right)^{3} using the power of a power property: \left(a^m\right)^n=a^{m\cdot n}. In the expression, m equals \frac{1}{3} and n equals 3.