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The difference of two logarithms of equal base $b$ is equal to the logarithm of the quotient: $\log_b(x)-\log_b(y)=\log_b\left(\frac{x}{y}\right)$
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$\log \left(\frac{x+1}{x}\right)=1$
Learn how to solve problems step by step online. Solve the logarithmic equation log(x+1)-log(x)=1. The difference of two logarithms of equal base b is equal to the logarithm of the quotient: \log_b(x)-\log_b(y)=\log_b\left(\frac{x}{y}\right). Take the variable outside of the logarithm. Any expression to the power of 1 is equal to that same expression. Simplifying the logarithm.