Final answer to the problem
$\ln\left(\sqrt[5]{x}\right)+\ln\left(\left(x^2-4\right)^7e^x\right)$
Got another answer? Verify it here!
Step-by-step Solution
Specify the solving method
1
Applying the product rule for logarithms: $\log_b\left(MN\right)=\log_b\left(M\right)+\log_b\left(N\right)$
$\ln\left(\sqrt[5]{x}\right)+\ln\left(\left(x^2-4\right)^7e^x\right)$
Final answer to the problem
$\ln\left(\sqrt[5]{x}\right)+\ln\left(\left(x^2-4\right)^7e^x\right)$