Final Answer
$\ln\left(\left(-2x^2+7x+6\right)^{\left(2x^2-7x-3\right)}\right)$
Got another answer? Verify it here!
Step-by-step Solution
Specify the solving method
1
Using the power rule of logarithms: $n\log_b(a)=\log_b(a^n)$, where $n$ equals $2x^2-7x-3$
$\ln\left(\left(-2x^2+7x+6\right)^{\left(2x^2-7x-3\right)}\right)$
Final Answer
$\ln\left(\left(-2x^2+7x+6\right)^{\left(2x^2-7x-3\right)}\right)$