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Factor the difference of squares $x^4-256$ as the product of two conjugated binomials
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$\lim_{x\to4}\left(\frac{\left(x^{2}+16\right)\left(x^{2}-16\right)}{x-4}\right)$
Learn how to solve limits by direct substitution problems step by step online. Find the limit (x)->(4)lim((x^4-256)/(x-4)). Factor the difference of squares x^4-256 as the product of two conjugated binomials. If we directly evaluate the limit \lim_{x\to 4}\left(\frac{\left(x^{2}+16\right)\left(x^{2}-16\right)}{x-4}\right) as x tends to 4, we can see that it gives us an indeterminate form. We can solve this limit by applying L'H么pital's rule, which consists of calculating the derivative of both the numerator and the denominator separately. After deriving both the numerator and denominator, the limit results in.