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Factor the difference of cubes: $a^3-b^3 = (a-b)(a^2+ab+b^2)$
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$\lim_{x\to2}\left(\frac{\left(x- 8^{\frac{1}{3}}\right)\left(x^2+8^{\frac{1}{3}}x+8^{\frac{2}{3}}\right)}{x-2}\right)$
Learn how to solve limits by direct substitution problems step by step online. Find the limit of (x^3-8)/(x-2) as x approaches 2. Factor the difference of cubes: a^3-b^3 = (a-b)(a^2+ab+b^2). Divide 1 by 3. Divide 1 by 3. Divide 2 by 3.