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Factor the difference of squares $x^2-4$ as the product of two conjugated binomials
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$\lim_{x\to-2}\left(\frac{\left(x+2\right)\left(x-2\right)}{x^3+8}\right)$
Learn how to solve limits by direct substitution problems step by step online. Find the limit (x)->(-2)lim((x^2-4)/(x^3+8)). Factor the difference of squares x^2-4 as the product of two conjugated binomials. Factor the sum of cubes: a^3+b^3 = (a+b)(a^2-ab+b^2). Simplify the fraction . Evaluate the limit \lim_{x\to-2}\left(\frac{x-2}{x^2-2x+4}\right) by replacing all occurrences of x by -2.