👉 Try now NerdPal! Our new math app on iOS and Android

Find the limit of $\frac{2x^3-2x^2+x-3}{x^3+2x^2-x+1}$ as $x$ approaches $\infty $

Step-by-step Solution

Go!
Math mode
Text mode
Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

Final Answer

$2$
Got another answer? Verify it here!

Step-by-step Solution

Specify the solving method

1

As it's an indeterminate limit of type $\frac{\infty}{\infty}$, divide both numerator and denominator by the term of the denominator that tends more quickly to infinity (the term that, evaluated at a large value, approaches infinity faster). In this case, that term is

$\lim_{x\to\infty }\left(\frac{\frac{2x^3-2x^2+x-3}{x^3}}{\frac{x^3+2x^2-x+1}{x^3}}\right)$
2

Separate the terms of both fractions

$\lim_{x\to\infty }\left(\frac{\frac{2x^3}{x^3}+\frac{-2x^2}{x^3}+\frac{x}{x^3}+\frac{-3}{x^3}}{\frac{x^3}{x^3}+\frac{2x^2}{x^3}+\frac{-x}{x^3}+\frac{1}{x^3}}\right)$
3

Simplify the fraction

$\lim_{x\to\infty }\left(\frac{2+\frac{-2x^2}{x^3}+\frac{x}{x^3}+\frac{-3}{x^3}}{1+\frac{2x^2}{x^3}+\frac{-x}{x^3}+\frac{1}{x^3}}\right)$
4

Simplify the fraction by $x$

$\lim_{x\to\infty }\left(\frac{2+\frac{-2x^2}{x^3}+\frac{x}{x^3}+\frac{-3}{x^3}}{1+\frac{2x^2}{x^3}+\frac{-1}{x^{2}}+\frac{1}{x^3}}\right)$
5

Simplify the fraction by $x$

$\lim_{x\to\infty }\left(\frac{2+\frac{-2x^2}{x^3}+\frac{1}{x^{2}}+\frac{-3}{x^3}}{1+\frac{2x^2}{x^3}+\frac{-1}{x^{2}}+\frac{1}{x^3}}\right)$
6

Simplify the fraction by $x$

$\lim_{x\to\infty }\left(\frac{2+\frac{-2x^2}{x^3}+\frac{1}{x^{2}}+\frac{-3}{x^3}}{1+\frac{2}{x}+\frac{-1}{x^{2}}+\frac{1}{x^3}}\right)$
7

Simplify the fraction by $x$

$\lim_{x\to\infty }\left(\frac{2+\frac{-2}{x}+\frac{1}{x^{2}}+\frac{-3}{x^3}}{1+\frac{2}{x}+\frac{-1}{x^{2}}+\frac{1}{x^3}}\right)$
8

Evaluate the limit $\lim_{x\to\infty }\left(\frac{2+\frac{-2}{x}+\frac{1}{x^{2}}+\frac{-3}{x^3}}{1+\frac{2}{x}+\frac{-1}{x^{2}}+\frac{1}{x^3}}\right)$ by replacing all occurrences of $x$ by $\infty $

$\frac{2+\frac{-2}{\infty }+\frac{1}{\infty ^{2}}+\frac{-3}{\infty ^3}}{1+\frac{2}{\infty }+\frac{-1}{\infty ^{2}}+\frac{1}{\infty ^3}}$
9

Any expression divided by infinity is equal to zero

$\frac{2+\frac{-2}{\infty }+\frac{1}{\infty ^{2}}+\frac{-3}{\infty ^3}}{1+0+\frac{-1}{\infty ^{2}}+\frac{1}{\infty ^3}}$
10

Add the values $1$ and $0$

$\frac{2+\frac{-2}{\infty }+\frac{1}{\infty ^{2}}+\frac{-3}{\infty ^3}}{1+\frac{-1}{\infty ^{2}}+\frac{1}{\infty ^3}}$
11

Any expression divided by infinity is equal to zero

$\frac{2+0+\frac{1}{\infty ^{2}}+\frac{-3}{\infty ^3}}{1+\frac{-1}{\infty ^{2}}+\frac{1}{\infty ^3}}$
12

Add the values $2$ and $0$

$\frac{2+\frac{1}{\infty ^{2}}+\frac{-3}{\infty ^3}}{1+\frac{-1}{\infty ^{2}}+\frac{1}{\infty ^3}}$
13

Infinity to the power of any positive number is equal to infinity, so $\infty ^2=\infty$

$2\cdot \infty -2\cdot \infty +\infty -3$
14

Infinity to the power of any positive number is equal to infinity, so $\infty ^2=\infty$

$\infty +2\cdot \infty - \infty +1$
15

Infinity to the power of any positive number is equal to infinity, so $\infty ^3=\infty$

$2+\frac{-2}{\infty }+\frac{1}{\infty }+\frac{-3}{\infty }$
16

Infinity to the power of any positive number is equal to infinity, so $\infty ^3=\infty$

$2+\frac{-2}{\infty }+\frac{1}{\infty }+\frac{-3}{\infty }$
17

Infinity to the power of any positive number is equal to infinity, so $\infty ^3=\infty$

$2+\frac{1}{\infty }+\frac{-3}{\infty }$
18

Infinity to the power of any positive number is equal to infinity, so $\infty ^3=\infty$

$\frac{2+\frac{1}{\infty ^{2}}+\frac{-3}{\infty ^3}}{1+\frac{-1}{\infty }+\frac{1}{\infty }}$
19

Infinity to the power of any positive number is equal to infinity, so $\infty ^{2}=\infty$

$\frac{2+\frac{1}{\infty }+\frac{-3}{\infty ^3}}{1+\frac{-1}{\infty }+\frac{1}{\infty }}$
20

Infinity to the power of any positive number is equal to infinity, so $\infty ^3=\infty$

$\frac{2+\frac{1}{\infty }+\frac{-3}{\infty }}{1+\frac{-1}{\infty }+\frac{1}{\infty }}$
21

Any expression divided by infinity is equal to zero

$\frac{2+\frac{1}{\infty }+\frac{-3}{\infty }}{1+0+\frac{1}{\infty }}$
22

Add the values $1$ and $0$

$\frac{2+\frac{1}{\infty }+\frac{-3}{\infty }}{1+\frac{1}{\infty }}$
23

Any expression divided by infinity is equal to zero

$\frac{2+\frac{1}{\infty }+\frac{-3}{\infty }}{1+0}$
24

Add the values $1$ and $0$

$\frac{2+\frac{1}{\infty }+\frac{-3}{\infty }}{1}$
25

Any expression divided by one ($1$) is equal to that same expression

$2+\frac{1}{\infty }+\frac{-3}{\infty }$
26

Any expression divided by infinity is equal to zero

$2+0+\frac{-3}{\infty }$
27

Add the values $2$ and $0$

$2+\frac{-3}{\infty }$
28

Any expression divided by infinity is equal to zero

$2+0$
29

Add the values $2$ and $0$

$2$

Final Answer

$2$

Exact Numeric Answer

$2$

Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

Solve using L'Hôpital's ruleSolve using factorizationSolve using rationalizationSolve without using l'Hôpital

Give us your feedback!

Function Plot

Plotting: $\frac{2x^3-2x^2+x-3}{x^3+2x^2-x+1}$

SnapXam A2
Answer Assistant

beta
Got a different answer? Verify it!

Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Your Math & Physics Tutor. Powered by AI

Available 24/7, 365.

Unlimited step-by-step math solutions. No ads.

Includes multiple solving methods.

Support for more than 100 math topics.

Premium access on our iOS and Android apps as well.

20% discount on online tutoring.

Choose your subscription plan:
Have a promo code?
Pay $39.97 USD securely with your payment method.
Please hold while your payment is being processed.
Create an Account