Final Answer
$\left(-1+e^{\frac{1}{z}}\right)z$
Got another answer? Verify it here!
Step-by-step Solution
Specify the solving method
1
Divide fractions $\frac{-1+e^{\frac{1}{z}}}{\frac{1}{z}}$ with Keep, Change, Flip: $a\div \frac{b}{c}=\frac{a}{1}\div\frac{b}{c}=\frac{a}{1}\times\frac{c}{b}=\frac{a\cdot c}{b}$
$\lim_{x\to\infty }\left(\left(-1+e^{\frac{1}{z}}\right)z\right)$
2
The limit of a constant is just the constant
$\left(-1+e^{\frac{1}{z}}\right)z$
Final Answer
$\left(-1+e^{\frac{1}{z}}\right)z$