Final answer to the problem
$eebgi\frac{nar^2ay}{-255l}=16=-\frac{1}{4}^2nr^2ay\cdot da$
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Step-by-step Solution
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1
Simplifying
$3+\frac{- 5^4}{3^2}=625eebgi\frac{\frac{nar\cdot ray}{l}}{1- {\left(-4\right)}^4}=16=2-\left(\frac{3}{2}\right)^2nr\cdot ray\cdot da$
2
Simplifying
$eebgi\frac{nar^2ay}{-255l}=16=-\frac{1}{4}^2nr^2ay\cdot da$
Final answer to the problem
$eebgi\frac{nar^2ay}{-255l}=16=-\frac{1}{4}^2nr^2ay\cdot da$