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Find the break even points of the polynomial $\left(\left(x+1\right)^3-\left(x-1\right)^3\right)\left(x+1\right)\left(x-1\right)$ by putting it in the form of an equation and then set it equal to zero
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$\left(\left(x+1\right)^3-\left(x-1\right)^3\right)\left(x+1\right)\left(x-1\right)=0$
Learn how to solve problems step by step online. Find the break even points of the expression ((x+1)^3-(x-1)^3)(x+1)(x-1). Find the break even points of the polynomial \left(\left(x+1\right)^3-\left(x-1\right)^3\right)\left(x+1\right)\left(x-1\right) by putting it in the form of an equation and then set it equal to zero. Break the equation in 3 factors and set each equal to zero, to obtain. Solve the equation (1). Factor the sum or difference of cubes using the formula: a^3\pm b^3 = (a\pm b)(a^2\mp ab+b^2).