Final Answer
Step-by-step Solution
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We could not solve this problem by using the method: FOIL Method
The sum of two terms multiplied by their difference is equal to the square of the first term minus the square of the second term. In other words: $(a+b)(a-b)=a^2-b^2$.
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$\left(x^2-1\right)\left(\left(x+1\right)^3-\left(x-1\right)^3\right)$
Learn how to solve special products problems step by step online. Expand the expression ((x+1)^3-(x-1)^3)(x+1)(x-1). The sum of two terms multiplied by their difference is equal to the square of the first term minus the square of the second term. In other words: (a+b)(a-b)=a^2-b^2.. Multiplying polynomials x^2-1 and \left(x+1\right)^3-\left(x-1\right)^3. Multiplying polynomials -1 and x^2-1. The cube of a binomial (sum) is equal to the cube of the first term, plus three times the square of the first by the second, plus three times the first by the square of the second, plus the cube of the second term. In other words: (a+b)^3=a^3+3a^2b+3ab^2+b^3 = (x)^3+3(x)^2(1)+3(x)(1)^2+(1)^3 =.