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$\int\left(y^2-3y\right)\left(y^2+3y\right)dy$
Learn how to solve integral calculus problems step by step online. Integrate the function (y^2-3y)(y^2+3y). Find the integral. Rewrite the expression \left(y^2-3y\right)\left(y^2+3y\right) inside the integral in factored form. The sum of two terms multiplied by their difference is equal to the square of the first term minus the square of the second term. In other words: (a+b)(a-b)=a^2-b^2.. Multiply the single term y^2 by each term of the polynomial \left(y^2-9\right).