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Find the break even points of the polynomial $\left(x-6\right)^2+\left(x+4\right)^2-\left(x+2\right)^2$ by putting it in the form of an equation and then set it equal to zero
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$\left(x-6\right)^2+\left(x+4\right)^2-\left(x+2\right)^2=0$
Learn how to solve problems step by step online. Find the break even points of the expression (x-6)^2+(x+4)^2-(x+2)^2. Find the break even points of the polynomial \left(x-6\right)^2+\left(x+4\right)^2-\left(x+2\right)^2 by putting it in the form of an equation and then set it equal to zero. A binomial squared (difference) is equal to the square of the first term, minus the double product of the first by the second, plus the square of the second term. In other words: (a-b)^2=a^2-2ab+b^2. Expand the expression \left(x+4\right)^2 using the square of a binomial: (a+b)^2=a^2+2ab+b^2. Add the values 36 and 16.