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- Integrate by partial fractions
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The product of two binomials of the form $(x+a)(x+b)$ is equal to the product of the first terms of the binomials, plus the algebraic sum of the second terms by the common term of the binomials, plus the product of the second terms of the binomials. In other words: $(x+a)(x+b)=x^2+(a+b)x+ab$
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$x^2+\left(-2+3\right)x-2\cdot 3\geq 0$
Learn how to solve problems step by step online. Solve the inequality (x-2)(x+3)>=0. The product of two binomials of the form (x+a)(x+b) is equal to the product of the first terms of the binomials, plus the algebraic sum of the second terms by the common term of the binomials, plus the product of the second terms of the binomials. In other words: (x+a)(x+b)=x^2+(a+b)x+ab. Subtract the values 3 and -2. Multiply -2 times 3. Add and subtract \displaystyle\left(\frac{b}{2a}\right)^2.