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Find the break even points of the polynomial $\left(x^2+4x-23\right)\left(x+5\right)$ by putting it in the form of an equation and then set it equal to zero
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$\left(x^2+4x-23\right)\left(x+5\right)=0$
Learn how to solve classify algebraic expressions problems step by step online. Find the break even points of the expression (x^2+4x+-23)(x+5). Find the break even points of the polynomial \left(x^2+4x-23\right)\left(x+5\right) by putting it in the form of an equation and then set it equal to zero. Break the equation in 2 factors and set each equal to zero, to obtain. Solve the equation (1). To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=1, b=4 and c=-23. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}.