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Find the break even points of the polynomial $\left(x^2+1\right)^2\left(x-1\right)^7x^3$ by putting it in the form of an equation and then set it equal to zero
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$\left(x^2+1\right)^2\left(x-1\right)^7x^3=0$
Learn how to solve problems step by step online. Find the break even points of the expression (x^2+1)^2(x-1)^7x^3. Find the break even points of the polynomial \left(x^2+1\right)^2\left(x-1\right)^7x^3 by putting it in the form of an equation and then set it equal to zero. Expand the expression \left(x^2+1\right)^2 using the square of a binomial: (a+b)^2=a^2+2ab+b^2. Break the equation in 3 factors and set each equal to zero, to obtain. Solve the equation (1).