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Find the break even points of the expression $\left(x+1\right)\left(x-2\right)\left(x+3+1\right)=0$

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sinh
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Solution

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Implicit differentiation | Advanced derivatives | AP Calculus AB | Khan Academy

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https://www.youtube.com/watch?v=yZLeN_9jjGg

Function Plot

Plotting: $\left(x+1\right)\left(x-2\right)\left(x+3+1\right)$

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1
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4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
◻2
◻◻
√◻
√

◻√◻
◻√
∞
e
π
ln
log
log◻
lim
d/dx
D□x
∫
∫◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

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$classify\left(x^2-1\cdot 4\cdot x\right)$

Main Topic: Classify algebraic expressions

An algebraic expression can be classified as a monomial, binomial, trinomial or polynomial, depending on the number of terms.

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