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We can multiply the polynomials $\left(n^3+4\right)\left(n^3-4\right)$ by using the FOIL method. The acronym F O I L stands for multiplying the terms in each bracket in the following order: First by First ($F\times F$), Outer by Outer ($O\times O$), Inner by Inner ($I\times I$), Last by Last ($L\times L$)
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$\begin{matrix}(F\times F)\:=\:(n^3)(n^3)\\(O\times O)\:=\:(n^3)(-4)\\(I\times I)\:=\:(4)(n^3)\\(L\times L)\:=\:(4)(-4)\end{matrix}$
Learn how to solve special products problems step by step online. Solve the product (n^3+4)(n^3-4). We can multiply the polynomials \left(n^3+4\right)\left(n^3-4\right) by using the FOIL method. The acronym F O I L stands for multiplying the terms in each bracket in the following order: First by First (F\times F), Outer by Outer (O\times O), Inner by Inner (I\times I), Last by Last (L\times L). Then, combine the four terms in a sum. Substitute the values of the products. Multiply 4 times -4.