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The product of two binomials of the form $(x+a)(x+b)$ is equal to the product of the first terms of the binomials, plus the algebraic sum of the second terms by the common term of the binomials, plus the product of the second terms of the binomials. In other words: $(x+a)(x+b)=x^2+(a+b)x+ab$
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$\left(\left(n^2\right)^2+\left(-1+7\right)n^2-7\right)\left(n^4-6n^2+7\right)$
Learn how to solve problems step by step online. Solve the product (n^2-1)(n^2+7)(n^4-6n^2+7). The product of two binomials of the form (x+a)(x+b) is equal to the product of the first terms of the binomials, plus the algebraic sum of the second terms by the common term of the binomials, plus the product of the second terms of the binomials. In other words: (x+a)(x+b)=x^2+(a+b)x+ab. Subtract the values 7 and -1. Simplify \left(n^2\right)^2 using the power of a power property: \left(a^m\right)^n=a^{m\cdot n}. In the expression, m equals 2 and n equals 2. We can multiply the polynomials \left(n^{4}+6n^2-7\right)\left(n^4-6n^2+7\right) by using the FOIL method. The acronym F O I L stands for multiplying the terms in each bracket in the following order: First by First (F\times F), Outer by Outer (O\times O), Inner by Inner (I\times I), Last by Last (L\times L).