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We can multiply the polynomials $\left(a^{\left(x+1\right)}-2b^{\left(x-1\right)}\right)\left(2b^{\left(x-1\right)}+a^{\left(x+1\right)}\right)$ by using the FOIL method. The acronym F O I L stands for multiplying the terms in each bracket in the following order: First by First ($F\times F$), Outer by Outer ($O\times O$), Inner by Inner ($I\times I$), Last by Last ($L\times L$)
Learn how to solve special products problems step by step online.
$\begin{matrix}(F\times F)\:=\:(a^{\left(x+1\right)})(2b^{\left(x-1\right)})\\(O\times O)\:=\:(a^{\left(x+1\right)})(a^{\left(x+1\right)})\\(I\times I)\:=\:(-2b^{\left(x-1\right)})(2b^{\left(x-1\right)})\\(L\times L)\:=\:(-2b^{\left(x-1\right)})(a^{\left(x+1\right)})\end{matrix}$
Learn how to solve special products problems step by step online. Solve the product (a^(x+1)-2b^(x-1))(2b^(x-1)+a^(x+1)). We can multiply the polynomials \left(a^{\left(x+1\right)}-2b^{\left(x-1\right)}\right)\left(2b^{\left(x-1\right)}+a^{\left(x+1\right)}\right) by using the FOIL method. The acronym F O I L stands for multiplying the terms in each bracket in the following order: First by First (F\times F), Outer by Outer (O\times O), Inner by Inner (I\times I), Last by Last (L\times L). Then, combine the four terms in a sum. Substitute the values of the products. When multiplying two powers that have the same base (a^{\left(x+1\right)}), you can add the exponents.