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$\int\left(7a^2-3b^2\right)\left(7a^2+3b^2\right)db$
Learn how to solve integral calculus problems step by step online. Find the integral of (7a^2-3b^2)(7a^2+3b^2). Find the integral. Rewrite the integrand \left(7a^2-3b^2\right)\left(7a^2+3b^2\right) in expanded form. Expand the integral \int\left(49a^{4}-9b^{4}\right)db into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int49a^{4}db results in: \frac{49}{5}a^{5}.