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Find the break even points of the polynomial $\left(7a^2b^3-5x^3\right)^2$ by putting it in the form of an equation and then set it equal to zero
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$\left(7a^2b^3-5x^3\right)^2=0$
Learn how to solve problems step by step online. Find the break even points of the expression (7a^2b^3-5x^3)^2. Find the break even points of the polynomial \left(7a^2b^3-5x^3\right)^2 by putting it in the form of an equation and then set it equal to zero. Removing the variable's exponent raising both sides of the equation to the power of \frac{1}{2}. We need to isolate the dependent variable , we can do that by simultaneously subtracting -5x^3 from both sides of the equation. Divide both sides of the equation by 7.