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$\int\left(\left(3x-2\right)^2-2\left(2x-3\right)\right)dx$
Learn how to solve integral calculus problems step by step online. Find the integral of (3x-2)^2-2(2x-3). Find the integral. Solve the product -2\left(2x-3\right). Expand the integral \int\left(\left(3x-2\right)^2-4x+6\right)dx into 3 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int\left(3x-2\right)^2dx results in: \frac{1}{9}\left(3x-2\right)^{3}.