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Find the break even points of the expression $\left(3x^3+2y^2\right)\left(9x^6-6x^3y^2+4y^4\right)$

Step-by-step Solution

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Solution

Final answer to the problem

$y=\sqrt{-\frac{3}{2}x^3},\:y=-\sqrt{-\frac{3}{2}x^3},\:9x^6-6x^3y^2+4y^4=0$
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Step-by-step Solution

How should I solve this problem?

  • Find break even points
  • Solve for x
  • Solve for y
  • Find the discriminant
  • Find the derivative
  • Solve by implicit differentiation
  • Solve for y'
  • Find dy/dx
  • Derivative
  • Integrate by partial fractions
  • Load more...
Can't find a method? Tell us so we can add it.
1

Find the break even points of the polynomial $\left(3x^3+2y^2\right)\left(9x^6-6x^3y^2+4y^4\right)$ by putting it in the form of an equation and then set it equal to zero

$\left(3x^3+2y^2\right)\left(9x^6-6x^3y^2+4y^4\right)=0$

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$\left(3x^3+2y^2\right)\left(9x^6-6x^3y^2+4y^4\right)=0$

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Learn how to solve problems step by step online. Find the break even points of the expression (3x^3+2y^2)(9x^6-6x^3y^24y^4). Find the break even points of the polynomial \left(3x^3+2y^2\right)\left(9x^6-6x^3y^2+4y^4\right) by putting it in the form of an equation and then set it equal to zero. Break the equation in 2 factors and set each equal to zero, to obtain. Solve the equation (1). We need to isolate the dependent variable , we can do that by simultaneously subtracting 3x^3 from both sides of the equation.

Final answer to the problem

$y=\sqrt{-\frac{3}{2}x^3},\:y=-\sqrt{-\frac{3}{2}x^3},\:9x^6-6x^3y^2+4y^4=0$

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Function Plot

Plotting: $\left(3x^3+2y^2\right)\left(9x^6-6x^3y^2+4y^4\right)$

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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
◻2
◻◻
√◻
√

◻√◻
◻√
∞
e
π
ln
log
log◻
lim
d/dx
D□x
∫
∫◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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