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Step-by-step Solution
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We will use the complete the square method to complete the polynomial $3x^2-3x$. First, factor both terms by the coefficient of the term $ax^2$, which is $3$
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$\left(3\left(x^2-x\right)\right)^3\left(-3x^2-x^{-1}\right)^2$
Learn how to solve polynomial factorization problems step by step online. Factor by completing the square (3x^2-3x)^3(-3x^2-x^(-1))^2. We will use the complete the square method to complete the polynomial 3x^2-3x. First, factor both terms by the coefficient of the term ax^2, which is 3. Add and subtract \left(\frac{b}{2}\right)^2, replacing b by it's value -1. Now we can factor x^2+-1x+\frac{1}{4} as a squared binomial of the form \left(x+\frac{b}{2}\right)^2. Multiply -1 times \frac{1}{2}.