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$\int\left(\left(3-x\right)^2-\left(x-3\right)\left(7x+4\right)-18+2x^2\right)dx$
Learn how to solve integral calculus problems step by step online. Find the integral of (3-x)^2-(x-3)(7x+4)+-182x^2. Find the integral. A binomial squared (difference) is equal to the square of the first term, minus the double product of the first by the second, plus the square of the second term. In other words: (a-b)^2=a^2-2ab+b^2. Multiplying polynomials -1 and x-3. Multiply the single term 7x+4 by each term of the polynomial \left(-x+3\right).