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$\int\left(\left(2x-3\right)^2-\left(2x+3\right)^2\right)dx$
Learn how to solve integral calculus problems step by step online. Integrate the function (2x-3)^2-(2x+3)^2. Find the integral. Expand the integral \int\left(\left(2x-3\right)^2-\left(2x+3\right)^2\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int\left(2x-3\right)^2dx results in: \frac{1}{6}\left(2x-3\right)^{3}. The integral \int-\left(2x+3\right)^2dx results in: -\frac{1}{6}\left(2x+3\right)^{3}.