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Find the break even points of the polynomial $\left(2x-3\right)\left(x^2+2xh+h^2\right)$ by putting it in the form of an equation and then set it equal to zero
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$\left(2x-3\right)\left(x^2+2xh+h^2\right)=0$
Learn how to solve integral calculus problems step by step online. Find the break even points of the expression (2x-3)(x^2+2xhh^2). Find the break even points of the polynomial \left(2x-3\right)\left(x^2+2xh+h^2\right) by putting it in the form of an equation and then set it equal to zero. Break the equation in 2 factors and set each equal to zero, to obtain. Solve the equation (1). We need to isolate the dependent variable , we can do that by simultaneously subtracting -3 from both sides of the equation.