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Find the break even points of the polynomial $\left(2x^2+4x+8\right)^2$ by putting it in the form of an equation and then set it equal to zero
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$\left(2x^2+4x+8\right)^2=0$
Learn how to solve classify algebraic expressions problems step by step online. Find the break even points of the expression (2x^2+4x+8)^2. Find the break even points of the polynomial \left(2x^2+4x+8\right)^2 by putting it in the form of an equation and then set it equal to zero. Removing the variable's exponent raising both sides of the equation to the power of \frac{1}{2}. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=2, b=4 and c=8. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Simplifying.