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Solve the product $\left(2x+3\right)\left(2x-3\right)$

Step-by-step Solution

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Final Answer

$4x^2-9$
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Step-by-step Solution

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We can multiply the polynomials $\left(2x+3\right)\left(2x-3\right)$ by using the FOIL method. The acronym F O I L stands for multiplying the terms in each bracket in the following order: First by First ($F\times F$), Outer by Outer ($O\times O$), Inner by Inner ($I\times I$), Last by Last ($L\times L$)

$\begin{matrix}(F\times F)\:=\:(2x)(2x)\\(O\times O)\:=\:(2x)(-3)\\(I\times I)\:=\:(3)(2x)\\(L\times L)\:=\:(3)(-3)\end{matrix}$

Learn how to solve special products problems step by step online.

$\begin{matrix}(F\times F)\:=\:(2x)(2x)\\(O\times O)\:=\:(2x)(-3)\\(I\times I)\:=\:(3)(2x)\\(L\times L)\:=\:(3)(-3)\end{matrix}$

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Learn how to solve special products problems step by step online. Solve the product (2x+3)(2x-3). We can multiply the polynomials \left(2x+3\right)\left(2x-3\right) by using the FOIL method. The acronym F O I L stands for multiplying the terms in each bracket in the following order: First by First (F\times F), Outer by Outer (O\times O), Inner by Inner (I\times I), Last by Last (L\times L). Then, combine the four terms in a sum. Substitute the values of the products. Multiply 3 times -3.

Final Answer

$4x^2-9$

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Plotting: $4x^2-9$

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5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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Main Topic: Special Products

Special products is the multiplication of algebraic expressions that follow certain rules and patterns, so you can predict the result without necessarily doing the multiplication.

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