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Expand the expression $\left(2w+5w^2-3w^3\right)\left(3w^2-5w^3\right)$

Step-by-step Solution

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Final Answer

$6w^{3}+5w^{4}-34w^{5}+15w^{6}$
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Step-by-step Solution

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We can multiply the polynomials $\left(2w+5w^2-3w^3\right)\left(3w^2-5w^3\right)$ by using the FOIL method. The acronym F O I L stands for multiplying the terms in each bracket in the following order: First by First ($F\times F$), Outer by Outer ($O\times O$), Inner by Inner ($I\times I$), Last by Last ($L\times L$)

$\begin{matrix}(F\times F)\:=\:(2w)(3w^2)\\(O\times O)\:=\:(2w)(-5w^3)\\(I\times I)\:=\:(5w^2-3w^3)(3w^2)\\(L\times L)\:=\:(5w^2-3w^3)(-5w^3)\end{matrix}$

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$\begin{matrix}(F\times F)\:=\:(2w)(3w^2)\\(O\times O)\:=\:(2w)(-5w^3)\\(I\times I)\:=\:(5w^2-3w^3)(3w^2)\\(L\times L)\:=\:(5w^2-3w^3)(-5w^3)\end{matrix}$

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Learn how to solve special products problems step by step online. Expand the expression (2w+5w^2-3w^3)(3w^2-5w^3). We can multiply the polynomials \left(2w+5w^2-3w^3\right)\left(3w^2-5w^3\right) by using the FOIL method. The acronym F O I L stands for multiplying the terms in each bracket in the following order: First by First (F\times F), Outer by Outer (O\times O), Inner by Inner (I\times I), Last by Last (L\times L). Then, combine the four terms in a sum. Substitute the values of the products. Multiplying polynomials 3w^2 and 5w^2-3w^3.

Final Answer

$6w^{3}+5w^{4}-34w^{5}+15w^{6}$

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Plotting: $6w^{3}+5w^{4}-34w^{5}+15w^{6}$

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7
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0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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Main Topic: Special Products

Special products is the multiplication of algebraic expressions that follow certain rules and patterns, so you can predict the result without necessarily doing the multiplication.

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