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$\int\left(2n-9\right)\left(2n+9\right)dn$
Learn how to solve integral calculus problems step by step online. Find the integral of (2n-9)(2n+9). Find the integral. Rewrite the integrand \left(2n-9\right)\left(2n+9\right) in expanded form. Expand the integral \int\left(4n^2-81\right)dn into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int4n^2dn results in: \frac{4}{3}n^{3}.