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$\int\left(2a^2+3b\right)\left(2a^2-3b\right)db$
Learn how to solve integral calculus problems step by step online. Find the integral of (2a^2+3b)(2a^2-3b). Find the integral. Rewrite the integrand \left(2a^2+3b\right)\left(2a^2-3b\right) in expanded form. Expand the integral \int\left(4a^{4}-9b^2\right)db into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int4a^{4}db results in: \frac{4}{5}a^{5}.