Final Answer
Step-by-step Solution
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Apply the product rule for differentiation: $(f\cdot g)'=f'\cdot g+f\cdot g'$, where $f=1-a+b$ and $g=b-a-1$
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$\frac{d}{db}\left(1-a+b\right)\left(b-a-1\right)+\left(1-a+b\right)\frac{d}{db}\left(b-a-1\right)$
Learn how to solve problems step by step online. Find the derivative of (1-ab)(b-a+-1). Apply the product rule for differentiation: (f\cdot g)'=f'\cdot g+f\cdot g', where f=1-a+b and g=b-a-1. The derivative of a sum of two or more functions is the sum of the derivatives of each function. The derivative of a sum of two or more functions is the sum of the derivatives of each function. The derivative of the constant function (1) is equal to zero.